Vertex and maximum value: graph it, tap the turning point
An original SAT-style practice question on the maximum of a quadratic, worked step by step in Desmos — the same graphing calculator that's built into Bluebook — with the x = −b/(2a) method alongside.
A model rocket is launched from a platform. Its height above the ground, in feet, t seconds after launch is modeled by h(t) = −16t² + 96t + 4. According to the model, what is the maximum height, in feet, the rocket reaches?
Step by step
Graph the function, using x for t
Desmos graphs in x and y, so swap t for x. The y-values here run into the hundreds, so if the curve shoots off the screen, tap the zoom-fit button (the magnifying glass) to bring the top into view.
Tap the turning point
Tap the curve, then tap the grey point at the very top. Desmos labels the vertex with both coordinates.
Pick the coordinate the question asked for
The question asks for the maximum height, which is the y-coordinate. The x-coordinate, 3, is when the rocket reaches it.
The vertex is at (3, 148): the rocket peaks 3 seconds after launch, at a height of 148 feet. Check: −16(3)² + 96(3) + 4 = −144 + 288 + 4 = 148 ✓.
Answering 3 — that's the time of the maximum (the x-coordinate), not the maximum height. Flip it around too: if a question asks when the maximum happens, the answer is the x-coordinate, not 148. Answer choices often include both on purpose.
Axis of symmetry: for y = ax² + bx + c, the vertex sits at x = −b/(2a). Here a = −16 and b = 96, so x = −96 / (2 · −16) = 3. Plug that back in: h(3) = 148. Since a is negative, the parabola opens down and the vertex is a maximum.
That's about as fast as graphing once you know the formula — the extra step is remembering to substitute back in for the y-value.
More walkthroughs: sum of a quadratic's solutions · systems of linear equations · quadratic roots · circle equations · exponential growth · line of best fit · solving for x by graphing · linear inequalities · absolute value equations · Desmos cheat sheet · all walkthroughs
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